# calculate confidence interval

1. (a) A utility company serves 50,000 households. As part of a survey of customer attitudes, they take a simple random sample (meaning drawing at random without replacement) of 750 of these households. The average number of television sets in the sample households turns out to be 1.86 and the standard deviation is 0.80. If possible, find a 95% confidence interval for the average number of television sets in all 50,000 households. If this isn’t possible, explain why not.

(b) Now, due to a budget constraint, the survey was conducted for only 18 households. The average number of television sets in the sample households turns out to be 1.86 and the standard deviation is 0.80. If possible, find a 95% confidence interval for the average number of television sets in all 50,000 households. If this isn’t possible, explain why not.

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